Engine mounts and head

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juddy
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Engine mounts and head

Post by juddy »

Hey guys,anyone know who I can buy a 2 into 1 cooling system head piece for my 98 CR 250 conversion and also need some engine mounts for it too. Cheers !!!
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matt_NC
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Post by matt_NC »

I followed Lonewolf's lead on this one:
Image

CRF450 outlet = 3/4" aluminum elbow

If you look inside the head and really think about it, there is no difference between a 2 into 1 that ends in 3/4", or one 3/4" outlet.

The only reason the CR500 head has two outlets is because the steelie frame and radiator design doesn't allow for a cross over on top.

One 3/4" outlet is actually more volume than two 1/2" outlets.

Just sayin' :mrgreen:
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AlisoBob
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Post by AlisoBob »

Running two outlet hoses (aka stock CR500 cooling path) addes that much more volume to the cooling system...
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Rue
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Post by Rue »

Buy the Kit for $35 from SolidBro and you are done :wink: here is the link:
http://www.bannedcr500riders.com/board/ ... php?t=8553

Make sure that you angle the right spigot if you go this route, learn from my mistake!! :oops:

Image
AFC Build link
http://www.bannedcr500riders.com/board/ ... 220#106220


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supermotoflunkie
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Location: Denver Colorado

Post by supermotoflunkie »

+1 on mounts and headstay

Im doing my 2nd gen 1 (first one ran out of moolah so I sold it) and am more than capaeable of making mounts from scratch but buying them is easy. I like easy
Jeff4510
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Joined: March 2nd, 2010, 8:58 am

Post by Jeff4510 »

matt_NC wrote:I followed Lonewolf's lead on this one:
Image



One 3/4" outlet is actually more volume than two 1/2" outlets.

Just sayin' :mrgreen:
That is some bad math imo but whatever, if you overheat let us know. Honda could have designed the bike however they wanted and yes that means they could have put a crossover thru the frame on the steelies. they spent millions and you've spent?
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MojoScojo
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Post by MojoScojo »

Pi * r^2

1/2 hole: r = .25 -> r^2 = .0625 -> * Pi = .19635

3/4 hole: r = .375 -> r^2 = .140625 -> * Pi = .44179


2 1/2 in holes = .19635 + .19635 -> .3927
1 3/4 in hole = .44179


3/4 hole wins. Where's the bad math?
No longer have a CR500.
07 Yamaha YZ250, 17 Husqvarna 701 Enduro
Get on with riding or get on with dying.
https://www.youtube.com/mojoscojo
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pstoffers
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Post by pstoffers »

MojoScojo wrote:Pi * r^2

1/2 hole: r = .25 -> r^2 = .0625 -> * Pi = .19635

3/4 hole: r = .375 -> r^2 = .140625 -> * Pi = .44179


2 1/2 in holes = .19635 + .19635 -> .3927
1 3/4 in hole = .44179


3/4 hole wins. Where's the bad math?
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AlisoBob
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Post by AlisoBob »

MojoScojo wrote:Pi * r^2
Friggin Mojo beat me to it....

:cry:

Area isnt the whole story, you have a boundry layer inside the hose that dosent flow so well, and in the stock CR500 Flowpath, you have a boundry layer in each hose, so the single 3/4" prolly' flows even more coolant than the simple surface area advantage caculation suggests...

Remember though, the water pump is at the bottom, and the radiator inlets are at the top...

Your basically trying to lift a water column about 24" of so, and it takes more head pressure than you might think.

The CR500 pump is a pretty ancient design, and its probably easier to lift 2 .500" water columns from the head to the radiators, than 1 .750" one.

I copied the CR500 coolant flow, and have never had a cooling issue.

Others have gone the 4 stroke path, with similar results.

It prolly dosent matter....

:?
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MojoScojo
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Post by MojoScojo »

Agreed. It's not all about flow.

Just off the top of my head, 2 hoses = more cooling surface.
No longer have a CR500.
07 Yamaha YZ250, 17 Husqvarna 701 Enduro
Get on with riding or get on with dying.
https://www.youtube.com/mojoscojo
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matt_NC
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Post by matt_NC »

Jeff4510 wrote: and you've spent?

More time in a math classroom than you apparently
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matt_NC
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Post by matt_NC »

AlisoBob wrote:
It prolly dosent matter....

:?

:cool:
Jeff4510
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Post by Jeff4510 »

All correct, my mistake. I apologize. You are dealing with more than simply size though- there's also pressure but likely not enough to effect this system (I hope).
MojoScojo wrote:Pi * r^2

1/2 hole: r = .25 -> r^2 = .0625 -> * Pi = .19635

3/4 hole: r = .375 -> r^2 = .140625 -> * Pi = .44179


2 1/2 in holes = .19635 + .19635 -> .3927
1 3/4 in hole = .44179


3/4 hole wins. Where's the bad math?
Jeff4510
Posts: 86
Joined: March 2nd, 2010, 8:58 am

Post by Jeff4510 »

I just spoke to my phd friend (mech eng). By making the hole "bigger" you've lowered the pressure. What's the point of this one line? One less rad hose?
matt_NC wrote:
Jeff4510 wrote: and you've spent?

More time in a math classroom than you apparently
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